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High-energy theory

Where a coupling stops being small

About 20 min if you have seen this material before, 50 min or so if it is new to you.

Background
Assumed background: separating the variables in a first-order differential equation. How strongly two particles interact is set by a number called a coupling, written gg. The surprising part is that gg is not a constant: it depends on the energy of the particles doing the interacting. An electron's charge measured in a low-energy experiment and the same charge measured at a collider are different numbers. The rate at which a coupling changes with energy is itself calculable, and the calculation produces a differential equation for gg with a coefficient fixed by which particles exist in the theory. Following a coupling from one energy to another with that equation is called The rate at which a coupling changes with energy scale, β(g)=μ dg/dμ\beta(g) = \mu\, dg/d\mu, which decides a marginal coupling's fate., and it underlies most of how particle physics relates experiments done at different energies. It is also what says whether a theory written down at low energy can be trusted at high energy, which is the subject of this problem. The equation below keeps only the first term of a series in g2g^2, with terms like g5g^5 on the right-hand side dropped. That approximation is good while gg is small. Part (c) explores what happens when gg is no longer small.
Write g(μ)g(\mu) for a coupling measured at energy μ\mu. To first order, dgdln⁡μ=b g316π2,\frac{dg}{d\ln\mu} = \frac{b\,g^3}{16\pi^2}, where bb is a dimensionless number fixed by the particle content of the theory. This same equation governs each of the Standard Model's forces, with a different bb for each. Two of them are given below, both with the coupling measured at the mass of the Z boson, μ=MZ=91.19\mu = M_Z = 91.19 GeV. The The charge carried by the Standard Model's U(1)U(1) gauge interaction, one of the three whose couplings run with energy. coupling, part of the electroweak force, has b=41/6b = 41/6 and gh(MZ)=0.3574g_h(M_Z) = 0.3574. Its bb is positive. The strong coupling, which binds quarks into protons, has b=−23/3b = -23/3 and αs(MZ)=0.1180±0.0009\alpha_s(M_Z) = 0.1180 \pm 0.0009, where αs=gs2/4π\alpha_s = g_s^2/4\pi. Its bb is negative, so it runs the other way, shrinking toward high energy rather than growing. That behaviour is called The behaviour of a coupling that shrinks toward high energy, which is what makes the strong interaction calculable at colliders..
The parts below integrate the equation for each coupling, and then ask how far the results can be trusted.
(a)
Take the hypercharge case. At what energy does 1/gh21/g_h^2 reach zero? Give log⁡10\log_{10} of that energy, with the energy in GeV.
(b)
gh(MZ)g_h(M_Z) comes from a measurement. How precisely would it have to be known for the energy in (a) to be pinned down within a factor of ten? Give the required fractional precision on ghg_h as a percentage.
(c)
Now the strong coupling, where bb has the opposite sign, so the coupling grows as the energy comes down. Keeping only the first term of the series is justified while gg is small, and that justification fails once gg approaches 1. Take αs=1\alpha_s = 1 as the point where it fails. At what energy is that reached? Give it in MeV.
(d)
The measured αs(MZ)\alpha_s(M_Z) carries an uncertainty of ±0.0009\pm 0.0009. What fractional uncertainty does that put on the answer to (c)? Give a percentage. This is the same calculation as (b), on an extrapolation that runs a few e-folds instead of ninety. Comparing the two answers is the point of asking twice.

Past 1.3 hr on this? That usually means a missing prerequisite rather than a lack of effort — worth reading up before pushing further, starting with Asymptotic freedom (Wikipedia).

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